Work, Energy & Power — Quick Summary

Mr Toogood's Physics · Mechanics

AQA 3.4.1.7 / 3.4.1.8
W = Fs cosθ
Work done
E_k = ½mv²
Kinetic energy
ΔE_p = mgΔh
GPE change
P = W/t = Fv
Power

Work

Working transfers energy in an organised way (particles move together); heating transfers it in a disordered way (temperature difference). Work is:

W = Fs cosθ

Only the force component in the direction of motion does work — a force at 90° to displacement does zero work. Units: N m, or joules.

Stretching objects (Hooke's law)

F = ke  (k = spring constant, N per m extension)

Since force grows steadily from zero, work done is the average force × extension:

W = ½Fe = ½ke²

Force–displacement graphs

Force against displacement graph, area under the line representing work done

Area under a force–displacement graph = work done.

For a straight line (e.g. Hooke's law), area = a simple triangle or rectangle. For a curved line: split into strips and sum, or integrate — W=∫F ds.

Deriving the energy equations

Both familiar equations come directly from W=Fs: substituting F=mv/t and s=½vt (from SUVAT, u=0) gives W=½mv²; substituting F=mg and s=Δh gives ΔE_p=mgΔh — it's the change in height that matters, not absolute height.

Conservation of energy

Energy is never created or destroyed, only transferred — the total in a closed system stays constant. With resistive forces present:

GPE lost = KE gained + work done against resistive forces
Especially useful when acceleration isn't constant, since SUVAT can't be applied directly — energy conservation still holds regardless.

Power & efficiency

P = W/t = Fv

One watt = one joule transferred per second. P=Fv is easy to overlook: the same resistive force at different speeds needs very different power (think wading through water quickly vs. slowly).

efficiency = useful output power / input power
Never exceeds 100% — a direct consequence of energy conservation; a lower efficiency just means more input energy goes somewhere other than the useful output.

Worked example: cyclist on a hill

Cyclist riding up a hill at a constant angle theta

At steady speed, driving force = weight component along the slope, mg sinθ.

At steady speed (equilibrium), driving force = mg sinθ. Combined with P=Fv, measured power and speed give θ.

Zig-zag path (same height gained, longer distance, same speed): takes longer, so the same energy is transferred over more time → lower power. Equivalently, the shallower effective angle means a smaller mg sinθ, so a smaller F and (via P=Fv) a smaller P — both routes agree.

Velocity-time graph of the cyclist freewheeling down the hill, curving to a plateau

Curved graph → acceleration isn't constant; use a tangent's gradient, not SUVAT.

Freewheeling downhill: GPE converts to KE, but resistive forces grow with speed, taking a larger share of the GPE lost per second — so acceleration decreases. Eventually resistive forces balance the weight component down the slope, and the cyclist reaches terminal velocity (the graph levels off).

Exam essentials

Key equations

  • W=Fscosθ   W=½ke²
  • E_k=½mv²   ΔE_p=mgΔh
  • P=Fv   eff.=P_useful/P_input

Graphical work

  • Area under an F–s graph = work done.
  • Straight line → triangle/rectangle.
  • Curved line → integrate, or sum strips.

Common slips

  • A curved v–t graph means acceleration isn't constant — SUVAT can't be used; find gradient from a tangent instead.
  • Only the force component along the direction of motion (F cosθ) does work.
  • Efficiency is always ≤100% — guaranteed by energy conservation.