Mr Toogood's Physics · Thermal physics
pV = constant at fixed T; a higher-temperature gas sits on a higher curve.
Extrapolating V–T (constant p) to V=0 gives −273.15 °C.
Extrapolating a volume–temperature graph (constant pressure) back to zero volume gives −273.15 °C = 0 K, absolute zero — the temperature at which particles theoretically have no kinetic energy left. The pressure–temperature graph extrapolates to the same intercept.
Combining the three laws gives the ideal gas equation, in two equivalent forms:
For comparing two states of the same gas, the constant terms cancel to give the combined gas law:
Work done = area under a p–V graph.
At constant pressure, the work done by an expanding gas is W = pΔV — this is the area under a horizontal line on a p–V graph. For a changing pressure (e.g. isothermal), find the area under the curve instead.