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3.6.1.3 Simple harmonic systems

Effects of damping on oscillations.

Damping

All oscillators experience friction. This frictional force will eventually reduce the amplitude of the oscillations down to zero. However over a short period of oscillations the amplitude does not change so we can discount friction.

Within the oscillator, energy is constantly being transferred between kinetic and potential energy. Overall the total amount of energy in conserved.

$$\large Total\;energy=E_{k}+E_{P}$$

The potential energy of the oscillator will be 0 when it is at its equilibrium position, where it has its maximum velocity. The potential energy will be maximum where the displacement x is maximum. The graph on the right shows how potential energy and kinetic energy vary with displacement. The curves are parabolic in shape and their sum is always the total energy.

$$E_{k}=\frac{1}{2}mv^{2}$$

The energy stored (potential energy) in a spring is,

$$E_{P}=\frac{1}{2}ke^{2}$$

Where x is the displacement from equilibrium, and k is the spring constant.

The total energy of the system is equal to the maximum energy stored when the spring is fully displaced at its amplitude,

$$E_{T}=\frac{1}{2}kA^{2}$$

Using this we can show that the kinetic energy of the oscillating spring is,

$$\large E_{k}=E_{T}-E_{P}=\frac{1}{2}k\left(A^{2}-x^{2} \right )$$

It is clear that the energy in an oscillator is constantly being transferred between potential and kinetic energy. When it is moving fastest, as it passes through the equilibrium, position, the Ek is maximum, and Ep is minimum. When the oscillator is at the maximum displacement then the Ek is minimum, and Ep is maximum. The total energy, for a free oscillator remains constant.

Common exam mistake

Kinetic energy is maximum at the equilibrium position (zero displacement) and zero at maximum displacement; potential energy is the exact opposite — zero at equilibrium, maximum at the extremes. This mirrors the velocity/acceleration pattern from the SHM page, but it's easy to muddle the two up when a question specifically asks about energy rather than motion.

kinetic and potential energy in an oscillator
Figure 1: This graph shows how the kinetic energy and potential energy of an oscillator varies with time.

Worth remembering

The statement "total energy remains constant" above applies to a free (undamped) oscillator, within a single cycle. The rest of this page is about damped oscillators, where friction removes a small amount of energy on every cycle — so while $E_k+E_p$ still holds true at any given instant, the maximum value of that total (and therefore the amplitude) gradually decreases over many cycles.

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Damped Oscillations

When an object oscillates it will lose energy to frictional forces, eventually the oscillations will diminish to zero. This is usually due to air resistance, by a large surface area to mass ratio or by the oscillator being immersed in a viscous fluid.

Often the decay is proportional to the velocity of the oscillator, which leads an exponential decay in the amplitude.

damped oscillators, amplitude against time
Figure 2: Three different types of damping, light, critical and heavy.
  • Light damping (blue line) is when the amplitude of each oscillation is fractionally less than the previous one. All practical oscillators, such as springs and pendulums are in fact lightly damped, and each oscillation is slightly smaller. The amount the oscillation is reduced by is called the damping constant.
  • Critical damping (red line) This is when the oscillations return to equilibrium in the shortest possible time. It is used when an oscillating system is not desirable, e.g. suspension systems, compass needles.
  • Heavy damping (green line) is when the oscillator very slowly returns to the equilibrium position.

Common exam mistake

More damping is not always "better" — it's easy to assume heavy damping returns a system to equilibrium fastest, since it sounds the most extreme. In fact critical damping is the fastest return without overshooting; heavy damping is slower than critical, not faster. This is exactly why car suspension and instrument needles are designed to be critically damped rather than heavily damped.

Damping oscillators can be very important, especially if that system can easily be made to resonate. These systems, such as bridges or car suspensions need to be damped to protect the structures and the users.

As the damped system has a decaying amplitude, it can be described using a decay equation such as:

$$\large A=A_{0}e ^{-\lambda t}$$

Where λ is the decay constant. The greater the decay constant the greater the amount of damping. The decay constant can be found by taking natural logs of both sides of the equation and plotting a graph of ln(A) against t. You will carry out an investigation into this in class.

Common exam mistake

Taking natural logs of $A=A_{0}e^{-\lambda t}$ gives $\ln A=\ln A_{0}-\lambda t$ — a straight line when you plot $\ln A$ against $t$ (not against $\ln t$). This is a semi-log plot, not a log-log plot; log-log plots are for power-law relationships like $y=ax^{n}$, which this isn't. The gradient of the $\ln A$ vs $t$ line gives $-\lambda$ directly — remember the negative sign, since the line slopes downward as the amplitude decays.

natural logs and the equation of a straight line
Figure 3: Using the equation of a straight line to understand logs

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An example of a damped oscillator

The video below shows a demonstration of how the exponential decay of an oscillating system can be verified

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Test yourself

Try the questions below to check your understanding of this topic. Numerical questions use different numbers each time, so you can attempt them more than once.

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